Physics - Electrostatics Question with Solution | TestHub

$\Rightarrow$ In metal all the charge is present on surface. $Q=6\mu C$ Total surface area $S=6a^2$ $=6\times {\left(5\times 10^{-2}\right)}^2$ $=6\times 25\times 10^{-4}$ $=150\times 10^{-4}{\mathrm{m}}^2$ Surface charge density $\sigma =\frac{Q}{S}$ $=\frac{6\times 10^{-6}}{150\times 10^{-4}}$ $=0.4\times 10^{-3}\mathrm{C}{\mathrm{m}}^{-2}$