The value of electric potential at a distance of 9 cm from the point charge 4 × 1 0 − 7 C is [ Given 4 π ε 0 1 = 9 × 1 0 9 N m 2 C − 2 ] :NEET 2024 (Re-NEET)

V = r k q = 9 × 1 0 9 × 9 × 1 0 − 2 4 × 1 0 − 7 = 4 × 1 0 4 V

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PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2024

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The value of electric potential at a distance of 9 cm from the point charge $4 \times 1 0^{- 7} C$ is $[$ Given $\frac{1}{4 π ε _{0}} = 9 \times 1 0^{9} N m^{2} C^{- 2}]$ :NEET 2024 (Re-NEET)

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$V = \frac{k q}{r}$ $= 9 \times 1 0^{9} \times \frac{4 \times 1 0 ^{- 7}}{9 \times 1 0 ^{- 2}}$ $= 4 \times 1 0^{4} V$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2024

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