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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minPYQ_2023

PhysicsMediumsingle choice

An electric dipole is placed as shown in the figure.

The electric potential (in $10^{2} V$ ) at point $P$ due to the dipole is ( $ε_{0}$ =permittivity of free space and $\frac{1}{4 π ε_{0}} = K$ )

NEET 2023 (All India)

Options:

Answer:

Solution:

The net electric potential at P can be calculated as follows-
$\begin{array}{rcl} V_{p} & = & \frac{K q}{(5 cm - 3 cm) \times \frac{1 m}{10^{2} cm}} - \frac{K q}{(5 cm + 3 cm) \times \frac{1 m}{10^{2} cm}} \\ = & K q \times 10^{2} \times (\frac{1}{2} - \frac{1}{8}) \\ = & \frac{3 K q}{8} \times 10^{2} V \end{array}$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2023

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