Physics - Electrostatics Question with Solution | TestHub

According to Gauss law, total electric flux through a closed surface is ${\varphi }_{\text{net }}=\frac{q}{{\epsilon }_0}$ $\therefore$ Total electric flux through the cube is ${\varphi }_T=\frac{Q\times 10^{-6}}{{\epsilon }_0}$ Since charge is placed at the centre of the cube, therefore flux through each face is same. Hence, $\varphi =\frac{1}{6}{\varphi }_T=\frac{1}{6}\times \frac{Q\times 10^{-6}}{{\epsilon }_0}$