If ∮ S E → · d S → = 0 over a surface, then:NEET 2023 (All India)

The electric flux through a surface is the surface integral of the normal component of the electric field E over that surface. As net flux given by, ∮ S E → · d S → = 0 , therefore total number of flux lines entering the surface must be equal to the number of flux lines leaving it.

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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsGauss LawEasy2 minPYQ_2023

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If $\oint_{S} \vec{E} \cdot d \vec{S} = 0$ over a surface, then:NEET 2023 (All India)

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The electric flux through a surface is the surface integral of the normal component of the electric field $E$ over that surface. As net flux given by, $\oint_{S} \vec{E} \cdot d \vec{S} = 0$ , therefore total number of flux lines entering the surface must be equal to the number of flux lines leaving it.

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law

⏱ 2mℹ️ Source: PYQ_2023

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