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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceEasy2 minPYQ_2021

PhysicsEasysingle choice

' $F$ ' is the force between the two identical charged particles placed at a distance ' $Y$ ' from each other. If the distance between the charges is reduced to half the previous distance, then force between them becomes

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Solution:

$F = \frac{1}{4 π ε _{0}} \cdot \frac{q ^{2}}{r ^{2}} ∴ \frac{F _{2}}{F _{1}} = (\frac{r _{1}}{r _{2}})^{2} = (2)^{2} = 4 ∴ F_{2} = 4 F_{1}$

Stream:MHT_CETSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2021

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