Physics - Electrostatics Question with Solution | TestHub

Combined capacity of $1 \mathrm{\mu }\mathrm{F}$ and $\mathrm{5 }\mathrm{\mu }\mathrm{F}\mathrm{ }$

 $= 1 + 5=$$6 \mathrm{\mu }\mathrm{F}$

Now, $\mathrm{4 }\mathrm{\mu }\mathrm{F}\mathrm{ }$and $\mathrm{6 }\mathrm{\mu }\mathrm{F}$ are in series.

$\therefore \frac{1}{C_s}=\frac{1}{4}+\frac{1}{6}=\frac{3+2}{12}=\frac{5}{12}$

$C_s=\frac{12}{\mathrm{5 }} \mathrm{\mu }\mathrm{F}$

Charge in the arm containing $\mathrm{4 }\mathrm{\mu }\mathrm{F}\mathrm{ }$capacitor is

$q=C_s\times V=\frac{12}{5}\times 10=24 \mathrm{\mu }\mathrm{C}$