Physics - Electrostatics Question with Solution | TestHub

When two concentric shells are connected by a wire the whole charge on inner shell is transferred to the outer shell.

Potential of the outer shell

${\text{V}}_{\text{i}}=\frac{\text{kQ}}{2\text{R}}+\frac{\text{k}\left(2\text{Q}\right)}{2\text{R}}$

${\text{V}}_{\text{i}}=\frac{3\text{kQ}}{2\text{R}}$

${\text{V}}_{\text{f}}=\frac{\text{k}\left(3\text{Q}\right)}{2\text{R}}$

$\therefore \Delta \text{V}={\text{V}}_{\text{f}}-{\text{V}}_{\text{i}}=0$