Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

A hollow charged metal sphere has a radius $r$ . If the potential difference between its surface and a point at a distance $3 r$ from the centre is $V$ , then the electric field intensity at distance $3 r$ from the centre is -

Options:

Answer:

Solution:

$V_{A} - V_{B} = \frac{k q}{r} - \frac{k q}{3 r} = V$

$\frac{k q}{r} \times \frac{2}{3} = V$

$E_{B} = \frac{k q}{{(3 r)}^{2}} = \frac{3}{2} \frac{V r}{{(3 r)}^{2}} = \frac{3 V r}{2 \times 9 \times r^{2}} = \frac{V}{6 r}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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