Physics - Electrostatics Question with Solution | TestHub

If an electron is accelerated through a potential difference of$\mathrm{V}$then its velocity is

$\mathrm{v}=\sqrt{\frac{2\mathrm{e}\mathrm{V}}{\mathrm{m}}}$

$\mathrm{v}=\sqrt{\frac{2\times \left(1.6\times 10^{-19}\right)\times 45.5}{9.1\times 10^{-31}}}$

$\mathrm{v}=4\times 10^6\mathrm{ }\mathrm{m} {\mathrm{s}}^{-1}$