Start Free Mock LoginAlready registered? Login here

Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A charge of $1 μ C$ is divided into two parts such that their charges are in the ratio of $2 : 3$ . These two charges are kept at a distance $1 m$ apart in vacuum. Then, the electric force between them (in $N$ ) is -

Options:

Answer:

Solution:

$\frac{q_{1}}{q_{2}} = \frac{2}{3}$

$q_{1} + q_{2} = 1 μC$

$\Rightarrow$ $q_{1} = \frac{2}{5} μ C, q_{2} = \frac{3}{5} μC$

$F = \frac{K q_{1} q_{2}}{r^{2}}$

$F = \frac{9 \times 1 0^{9} \times \frac{2}{5} \times \frac{3}{5} \times 1 0^{- 12}}{{(1)}^{2}}$

$= 0.00216 N$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...