Physics - Electrostatics Question with Solution | TestHub

Electric field due to one surface of the large metal plate,



The projected electron's motion will be on a curved path like a projectile.

$\therefore$AB will be maximum when$\theta =45°$

Range$A{B}_{max}=\frac{u^2}{a}$

$a=\frac{\rho E}{m}=\frac{\mathrm{\rho }\sigma }{2{\epsilon }_{0}m}$

$=\frac{u^2}{\frac{\rho \sigma }{2{\epsilon }_{0}m}}=\frac{2{\epsilon }_{0}m{u}^2}{\rho \sigma }$