Physics - Electrostatics Question with Solution | TestHub

The net potential on the surface of earthed conductor is zero.



$\therefore \text{V}=\frac{{\text{q}}_0}{4\pi {\epsilon }_0\text{r}}+\frac{\text{q}}{4\pi {\epsilon }_0\text{d}}=0$

$\therefore {\text{q}}_0=-\frac{\text{qr}}{\text{d}}$