An infinitely long wire is kept along z -axis from z = - ∞ to z = + ∞ , having uniform linear charge density 10 9 nC m - 1 The electric field E → at point 6 cm , 8 cm , 10 cm will be:

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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsGauss LawEasy2 minPYQ_2020

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An infinitely long wire is kept along $z$ -axis from $z = - \infty$ to $z = + \infty$ , having uniform linear charge density $\frac{10}{9} nC m^{- 1}$ The electric field $\vec{E}$ at point $(6 cm, 8 cm, 10 cm)$ will be:

Options:

Answer:

Solution:

$E = \frac{2 k λ}{d} = \frac{2 \times 9 \times 10^{9} \times (\frac{10}{9}) \times 10^{- 9}}{10 \times 10^{- 2}} = 200 V m^{- 1}$

As field is radial out, there is no component of it in $Z$ direction.

$\vec{E} = 200 \cos 53 \hat{i} + 200 \sin 53 \hat{j}$

$= (120 \hat{i} + 160 \hat{j}) N C^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law

⏱ 2mℹ️ Source: PYQ_2020

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