Physics - Electrostatics Question with Solution | TestHub

For series,${$ C^{\prime }$}^{}=\frac{{\mathit{\text{C}}}_1\times {\mathit{\text{C}}}_2}{{\mathit{\text{C}}}_1+{\mathit{\text{C}}}_2}=\frac{4\times 4}{4+4}=2\mathrm{ \mu }\text{F}$

For parallel,${\mathit{\text{C}}}_{\text{eq}}={$ C^{\prime }$}^{}+{\mathit{\text{C}}}_3=2+4=6 \mathrm{ \mu }\text{F}$

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