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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

In the given system a capacitor of plate area $A$ is charged up to charge $q$ . The mass of each plate is $m_{2}$ . The lower plate is rigidly fixed. Find the value of $m_{1}$ so that the system is in equilibrium -

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Answer:

Solution:

$T = F e + m_{2} g \dots . (1) (f o r u p p e r p l a t e)$

$T = m_{1} g \dots . (2) (f o r m_{1})$

$∴ m_{1} g = \frac{q^{2}}{2 A ε_{0}} + m_{2} g$

$\Rightarrow m_{1} = \frac{q^{2}}{2 A ε_{0} g} + m_{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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