Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

The potential of the electric field produced by point charge at any point $(x, y, z)$ is given by $V = 3 x^{2} + 5,$ where $x, y$ are in metres and V is in volts. The intensity of the electric field at $(- 2 m, 1 m, 0 m)$ is

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Answer:

Solution:

Potential $(V) = 3 x^{2} + 5$

Intensity of the electric field=

$\frac{-d V}{d x} = 6 x$

$∴ E a t x = - 2$

$=- 6 (- 2) =+ 12 V m^{- 1}$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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