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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Three capacitors each of capacitance $C = 2 μ F$ are connected with a battery of emf $30 V$ as shown in the figure. When the switch $S$ is closed, the heat generated in the circuit will be

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Answer:

Solution:

$U_{i} = \frac{1}{2} C {(\frac{V}{3})}^{2} + \frac{1}{2} C {(\frac{V}{3})}^{2} + \frac{1}{2} (C) {(\frac{2 V}{3})}^{2}$
$U_{f} = \frac{1}{2} C V^{2}$
$W_{b} = \frac{C V^{2}}{3}$
$Δ H = [W_{b} - (U_{f} - U_{i})] = \frac{C V^{2}}{6} = 0.30 m J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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