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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

A thin spherical conducting shell of radius $R$ is given a charge $q$ . Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at the point $P$ at a distance $\frac{R}{2}$ from the centre of the shell is

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Answer:

Solution:

Potential due to point charge
$V_{1} = \frac{Q}{4 π ε_{0} (\frac{R}{2})}$

Potential due to shell at inside point

$V_{2} = V_{\frac{R}{2}} = V_{s u r f a c e}$

$V_{2} = \frac{q}{4 π ε_{0} R}$

$V_{t o t a l} = \frac{2 Q}{4 π ε_{0} R} + \frac{q}{4 π ε_{0} R}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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