Physics - Electrostatics Question with Solution | TestHub

The figure is a balanced Wheatstone bridge, so diagonal capacitor will be ineffective.

So, the equivalent circuit will be as shown in the figure.




Equivalent capacitance of upper arms in series

$C_1=\frac{2\times 2}{2+2}=\mathrm{1 }\mathrm{\mu }\mathrm{F}$

Similarly, for lower arm

$C_2=\mathrm{1 }\mathrm{\mu }\mathrm{F}$

$\therefore C_{AB}=C_1+C_2$

$=1+1=\mathrm{2 }\mathrm{\mu }\mathrm{F}$