An electric dipole is placed at an angle of 30 ° with an electric field intensity 2 × 10 5 N C - 1 . It experiences a torque equal to 4 N m . The charge on the dipole, if the dipole length is 2 cm , is

τ = P E sin ⁡ θ ⇒ τ = q l E sin ⁡ θ ⇒ q = τ l E sin ⁡ θ = 4 2 × 10 - 2 × 0.5 × 2 × 10 5 = 2 m C

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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsdipoleEasy2 minPYQ_2020

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An electric dipole is placed at an angle of $30 °$ with an electric field intensity $2 \times 10^{5} {N C}^{- 1}$ . It experiences a torque equal to $4 N m$ . The charge on the dipole, if the dipole length is $2 cm$ , is

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Answer:

Solution:

$τ = P E \sin θ$

$\Rightarrow τ = q l E \sin θ$

$\Rightarrow q = \frac{τ}{l E \sin θ}$

$= \frac{4}{2 \times 10^{- 2} \times 0.5 \times 2 \times 10^{5}} = 2 mC$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:dipole

⏱ 2mℹ️ Source: PYQ_2020

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