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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

The figure shows three circular arcs, each of radius $R$ and total charge as indicated. The net electric potential at the centre of curvature is -

Options:

Answer:

Solution:

Since electric potential is scalar quantity therefore :

$V = V_{1} + V_{2} + V_{3}$

$= \frac{1}{4π ε_{0}} . \frac{Q}{R} + \frac{1}{{4π ε}_{0}} [\frac{- 2Q}{R}] + \frac{1}{{4π ε}_{0}} [\frac{3Q}{R}]$

$= \frac{1}{4 π ε_{0}} . [\frac{2 Q}{R}]$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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