Physics - Electrostatics Question with Solution | TestHub

$E_{\mathrm{P}}=\frac{kq}{r^2}$

$E_{\mathrm{Q}}=\frac{kq}{{\left(2r\right)}^2}+\frac{k3q}{{\left(2r\right)}^2}=\frac{4kq}{4r^2}$

Because the charges are positive on both the spheres so electric field at point$Q$is in the same direction, so they added algebraically

$E_{\mathrm{P}}\mathrm{ }:E_{\mathrm{Q}}=1\mathrm{ }:1$