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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2015

PhysicsEasysingle choice

If potential(in $volts$ ) in a region is expressed as $V (x, y, z) = 6 x y - y + 2 y z$ , the electric field(in $N C^{- 1}$ ) at point $(1, 1, 0)$ isNEET 2015 (Phase 2)

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Answer:

Solution:

$V = 6 x y - y + 2 y z$

$\vec{E} = - (\frac{\partial V}{\partial x} \hat{i} + \frac{\partial V}{\partial y} \hat{j} \frac{\partial V}{\partial z} \hat{k})$

$\vec{E} = - [(6 y) \hat{i} + (6 x - 1 + 2 z) \hat{j} + (2 y) \hat{k}]$

$\vec{E} (1, 1, 0) = - (6 \hat{i} + 5 \hat{j} + 2 \hat{k})$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2015

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