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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceMedium2 minPYQ_2009

PhysicsMediumsingle choice

If the linear charge density of a cylinder is $4 μ Cm^{- 1}$ then electric field intensity at point $3.6 cm$ from axis is

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Answer:

Solution:

For a charged cylinder $E = \frac{λ}{2 π ε _{0} r} = \frac{4 \times 1 0 ^{- 6} \times 18 \times 1 0 ^{9}}{3.6 \times 1 0 ^{- 2}} = 2 \times 1 0^{6} NC^{- 1}$

Stream:MHT_CETSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2009

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