The electric potential at a point in free space due to a charge Q coulomb is Q × 1 0 11 volts. The electric field at that point isNEET 2008 (Mains)

V E = 4 π ε 0 1 ⋅ R Q = Q × 1 0 11 volt = 4 π ε 0 1 ⋅ R 2 Q = R V = Q × 1 0 11 × 4 π ε 0 × 1 0 11 [ from ...(i) ] = 4 π ε 0 Q × 1 0 22 volt / m

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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minPYQ_2008

PhysicsMediumsingle choice

The electric potential at a point in free space due to a charge $Q$ coulomb is $Q \times 1 0^{11}$ volts. The electric field at that point isNEET 2008 (Mains)

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$V E = \frac{1}{4 π ε _{0}} \cdot \frac{Q}{R} = Q \times 1 0^{11} volt = \frac{1}{4 π ε _{0}} \cdot \frac{Q}{R ^{2}} = \frac{V}{R} = Q \times 1 0^{11} \times 4 π ε_{0} \times 1 0^{11} [from ...(i)] = 4 π ε_{0} Q \times 1 0^{22} volt / m$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2008

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