Physics - Electrostatics Question with Solution | TestHub

The net electric potential is algebraic sum of potential due to individual point charges. $\begin{array}{rl}\mathrm{V}& =\frac{1}{4\pi {\in }_0}\left[\frac{{\mathrm{q}}_1}{{\mathrm{r}}_1}+\frac{{\mathrm{q}}_2}{{\mathrm{r}}_2}+\frac{{\mathrm{q}}_3}{{\mathrm{r}}_3}\right]\\ \mathrm{V}& =\frac{1}{4\pi {\epsilon }_0}\left[\frac{1\times 10^{-6}}{0.2}-\frac{2\times 10^{-6}}{0.2}+\frac{3\times 10^{-6}}{0.3}\right]\\ & =9\times 10^9[5-10+10]\times 10^{-6}\\ & =9\times 10^3[5]=45\times 10^3\mathrm{V}=45\mathrm{kV}\end{array}$