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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyHard2 minPYQ_2002

PhysicsHardsingle choice

Identical charges $(- q)$ are placed at each corner of a cube of side ' $b$ ' then the electrical potential energy of charge (+ $q$ ) which is placed at the centre of cube will be:NEET 2002

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Answer:

Solution:

Distance between the charge $- q$ and $+ q$ is $r = \frac{( 2 b ) ^{2} + ( b ) ^{2}}{2} = \frac{3}{2} b$ Electric potential energy of charge $+ q is v = 8 \times \frac{1}{4 π ε _{0}} \frac{a ( - a )}{r} = 8 \times \frac{1}{4 π ε _{0}} \frac{q ( - a )}{\frac{3}{2} b} U = \frac{- 4 q ^{2}}{3 π ε _{0} b}$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2002

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