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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceHard2 minPDF

PhysicsHardsingle choice

Passage / Comprehension

An uncharged soap bubble of radius $r_{1}$ is electrified. It expands to radius $r_{2}$ and reaches potential V. The surrounding atmospheric pressure is $P_{0}$ and the surface tension is T. Charge is uniformly distributed.

After the sphere has been electrified and has attained a radius $r_{2}$ and potential V, the force of interaction between 2 halves (hemisphere) of the spherical bubble due to electrostatic repulsion will be :-

Options:

Answer:

Solution:

$F = \frac{ϵ _{0} E ^{2}}{2} π r_{2}^{2}$

$E = \frac{V}{r _{2}}$

$F = \frac{π ϵ _{0} V ^{2}}{2}$

Hence option A.

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

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