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PhysicsElectrostaticsConductorMedium2 minPDF

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A neutral conducting spherical shell is kept near a charge q as shown. The potential at point P due to the induced charges is

Answer:

Solution:

The conductor is an equipotential.

$V_{P} = \frac{k q}{r} + V_{in d u ce d}$

The potential on the shell due to external charge plus induced charges is constant.

$V_{in d u ce d} = \frac{k q}{r '} - \frac{k q}{r}$

Hence option C.

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Conductor

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