An electric dipole with dipole moment 1 0 − 9 C-m is placed along the x-axis. The electric field in the region is given by E = ( 5 x 2 ) i ^ N/C. If the dipole is located at x = 1 m, find the magnitud

Question

An electric dipole with dipole moment 1 0 − 9 C-m is placed along the x-axis. The electric field in the region is given by E = ( 5 x 2 ) i ^ N/C. If the dipole is located at x = 1 m, find the magnitude of the force (in nN) experienced by the dipole.

TestHub · Accepted Answer

The force on an electric dipole in a non-uniform electric field is given by F = p d x d E ​ . Given p = 1 0 − 9 C-m and E = 5 x 2 . Therefore, d x d E ​ = 10 x . At x = 1 m, d x d E ​ = 10 ( 1 ) = 10 N/C-m. F = ( 1 0 − 9 C-m ) × ( 10 N/C-m ) = 1 0 − 8 N. In nanoNewtons, F = 10 × 1 0 − 9 N = 10 nN.

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