Physics - Electrostatics Question with Solution | TestHub

The electric potential due to a short electric dipole at a point $(r,\theta )$ is given by $V=\frac{kp\cos \theta }{r^2}$. Given $p=10^{-8}$ C-m, $r=1$ m, $\theta =60^{\circ }$, and $k=9\times 10^9$ N m${}^2$ /C${}^2$.$V=\frac{(9\times 10^9)\times (10^{-8})\times \cos 60^{\circ }}{(1{)}^2}=90\times 0.5=45$ V. The electric potential at the given point is 45 V.