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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minPYQ_2024

PhysicsMediumnumerical

At the centre of a half ring of radius $R = 10 cm$ and linear charge density $4 nC m^{- 1}$ , the potential is $x π V$ . The value of $x$ is _______

Answer:

36.00

Solution:

Potential at centre of half ring $V = \frac{K Q}{R} V = \frac{K λπ R}{R} V = K λπ \Rightarrow V = 9 \times 1 0^{9} \times 4 \times 1 0^{- 9} π V = 36 π$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2024

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