In a cuboid of dimension 2 L × 2 L × L , a charge q is placed at the centre of the surface S having area of 4 L 2 . The flux through the opposite surface to S is given by

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Assume a similar cuboid on top of the given cuboid to make symmetry about charge. Thus, it becomes a cube of length $2 L$ .

Flux passing through whole cube is $ϕ = \frac{q}{\in_{0}}$ (Gauss's Law).

Since, total faces are $6$ , so flux passing through shaded face $= \frac{q}{6 \in_{0}}$ .

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