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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minPYQ_2023

PhysicsMediumsingle choice

If $V$ is the gravitational potential due to sphere of uniform density on its surface, then its value at the centre of sphere will be:

Options:

Answer:

D

Solution:

The magnitude of gravitational potential of a solid sphere at a distance $r$ from the centre is
$V = \frac{- G M}{2 R^{3}} (3 R^{2} - r^{2})$
At $r = R$ , $V = \frac{- G M}{R}$ .
At $r = 0$ , $V' = \frac{- G M}{2 R^{3}} (3 R^{2}) = \frac{- 3 G M}{2 R}$
Clearly, $V' = \frac{3 V}{2}$ .

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2023

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