An electron revolves around an infinite cylindrical wire having uniform linear charge density 2 × 10 - 8 C m - 1 in circular path under the influence of attractive electrostatic field as shown in the

Question

An electron revolves around an infinite cylindrical wire having uniform linear charge density $2 \times 10^{- 8}$ $C m^{- 1}$ in circular path under the influence of attractive electrostatic field as shown in the figure. The velocity of electron with which it is revolving is ______________ $\times 10^{6} m s^{- 1}$ . Given mass of electron $= 9 \times 10^{- 31} kg$

TestHub · Accepted Answer

The electric field is given by E = 2 k λ r The required centripetal force is F = m v 2 r The force due to the field is equal to the required centripetal force, ⇒ 2 k λ r e = m v 2 r ⇒ v = 2 k λ e m = 2 × 9 × 10 9 × 2 × 10 - 8 × 1 . 6 × 10 - 19 9 × 10 - 31 = 1 . 6 × 4 × 10 13 = 4 × 2 × 10 6 m s - 1 = 8 × 10 6 m s - 1

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