27 identical drops are charged at 22 V each. They combine to form a bigger drop. The potential of the bigger drop will be _____ V .

Question

TestHub · Accepted Answer

Total volume of the drop will remain unchanged,

So, $27 \times (\frac{4}{3} π r^{3}) = \frac{4}{3} π R^{3}$

$\Rightarrow R = 3 r$

Potential of the small drops, $22 = \frac{k q}{r}$

For bigger drop, potential will be

$V = \frac{k (27 q)}{(3 r)} = 9 (\frac{k q}{r}) = 9 \times 22 = 198 V$

Physics - Elecrostatics Question with Solution | TestHub