Physics - Electrostatics Question with Solution | TestHub

The electric field in a region is given by$\overrightarrow{E}=\left(\frac{3}{5}{E}_0\hat{\mathrm{i}}+\frac{4}{5}{E}_0\hat{\mathrm{j}}\right) \mathrm{N} {\mathrm{C}}^{-1}$. The ratio of flux of reported field through the rectangular surface of area$0.2 {\mathrm{m}}^2$(parallel to$y-z$plane) to that of the surface of area$0.3 {\mathrm{m}}^2$(parallel to$x-z$plane) is$a:b=a:2,$where$a=?$[Here$\hat{\mathrm{i}}, \hat{\mathrm{j}}$and$\hat{\mathrm{k}}$are unit vectors along$x, y$and$z$-axes respectively]