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PhysicsElectrostaticsGauss LawEasy2 minPYQ_2021
PhysicsEasynumerical

The electric field intensity is produced by the radiation coming from a100 Wbulb at a distance of3 misE. The electric field intensity produced by the radiation coming from60 Wat the same distance isx5E. Where the value ofx=_________ .

Answer:
3.00
Solution:

cε0E2=1004π×32

cε0x5E2=604π×32

x5=35

x=3

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law
2mℹ️ Source: PYQ_2021

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