Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceMedium2 minPYQ_2020

PhysicsMediumsingle choice

Charges $Q_{1}$ and $Q_{2}$ are at points $A$ and $B$ of a right-angled triangle $O A B$ . The resultant electric field at point $O$ is perpendicular to the hypotenuse, then $Q_{1} / Q_{2}$ is proportional to:

Options:

Answer:

Solution:

Using triangle properties

$\tan θ = \frac{x_{1}}{x_{2}} \tan θ = \frac{E_{2}}{E_{1}} = \frac{K Q_{2} / x_{2}^{2}}{K Q_{1} / x_{1}^{2}} \Rightarrow \frac{x_{1}}{x_{2}} = \frac{K Q_{2} / x_{2}^{2}}{K Q_{1} / x_{1}^{2}}$

$\frac{Q_{1}}{Q_{2}} =$ $\frac{x_{1}}{x_{2}}$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...