Physics - Electrostatics Question with Solution | TestHub

$\mathrm{E}=150 \mathrm{N}/\mathrm{C}$

We know that$$$\varphi =\stackrel{}{}\overrightarrow{\text{E}}\stackrel{}{}·\stackrel{}{}\overrightarrow{\text{A}}$

$=\text{E}\times 4\pi {}^{}{\text{r}}^2$

$=150\times 4\pi \times {\left({}_{}\right)}^{}{\left({\text{R}}_{\text{e}}\right)}^{\left({}_{}\right)}$

Now,$$$\varphi =\frac{{}_{}}{}\frac{{\text{Q}}_{\text{in}}}{{}_{}}$





${\text{Q}}_{\text{in}}{}_{}=\varphi {}_{}{\in }_{\text{o}}{}_{}=150\times 4\pi {\left({}_{}\right)}^{}{\left({\text{R}}_{\text{e}}\right)}^{\left({}_{}\right)}{}^{}\times \text{8.85}\times 1{}^{}{0}^{}{}^{}\text{C}$

$=150\times 4\pi {\left\{\right\}}^{}{\left\{\text{6.37}\times 1{}^{}{0}^6\right\}}^{\left\{{}^{}\right\}}{}^{}\times \text{8.85}\times 1{}^{}{0}^{}$

$=600\pi \times \text{6.37}\times \text{6.37}\times \text{8.85}C$

$= 680\text{kC}$

$$As Electric field is inward,$\mathrm{Q}$will be negative