Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyMedium2 minPYQ_2013

PhysicsMediumsingle choice

A point charge of magnitude $+ 1 μ C$ is fixed at $(0$ , $0, 0)$ . An isolated uncharged spherical conductor, is fixed with its center at $(4, 0, 0)$ . The potential and the induced electric field at the centre of the sphere is :

Options:

Answer:

Solution:

$q = 1 μ C = 1 \times 1 0^{- 6} C$ $r = 4 cm = 4 \times 1 0^{- 2} m$ Potential $V = \frac{kq}{r}$ $= \frac{9 \times 1 0 ^{9} \times 1 0 ^{- 6}}{4 \times 1 0 ^{- 2}} = 2.25 \times 1 0^{5} V .$ Induced electric field $E = - \frac{kq}{r ^{2}}$ $= \frac{9 \times 1 0 ^{9} \times 1 \times 1 0 ^{- 6}}{16 \times 1 0 ^{- 4}} = - 5.625 \times 1 0^{6} V / m$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2013

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