Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyHard2 minPYQ_2013

PhysicsHardsingle choice

A charge Q is uniformly distributed over a long rod AB of length L as shown in the figure. The electric potential at the point O lying at a distance L from the end A is :

Options:

Answer:

Solution:

$V = \int_{L}^{2 L} \frac{kdq}{x}$

$= \int_{L}^{2 L} \frac{1}{4 π ε_{0}} \frac{(\frac{Q}{L}) dx}{x}$

$= \frac{Q}{4 π ε_{0} L} ℓ n (2)$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2013

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