A charged particle q is shot towards another charged particle Q which is fixed, with a speed v it approaches Q upto a closest distance r and then returns. If q were given a speed 2 v , the closest dis

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A charged particle q is shot towards another charged particle Q which is fixed, with a speed v it approaches Q upto a closest distance r and then returns. If q were given a speed 2 v , the closest distances of approach would be

TestHub · Accepted Answer

By principle of conservation of energy Finally, 2 1 ​ m ( 2 v ) 2 = r 2 K qQ ​ Equation (i) ÷ (ii), ​ 4 1 ​ = r r ′ ​ ⇒ r ′ = 4 r ​ . ​

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