Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceHard2 minPYQ_2003

PhysicsHardsingle choice

Three charges $- q_{1}, + q_{2}$ and $- q_{3}$ are placed as shown in the figure. The $x$ -component of the force on $- q_{1}$ is proportional to

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Answer:

Solution:

The force body diagram $F_{1} = \frac{1}{4 π ε _{0}} \cdot \frac{q _{1} q _{3}}{a ^{2}}$ $F_{2} = \frac{1}{4 π ε _{0}} \cdot \frac{q _{1} q _{3}}{b ^{2}}$
$F_{X} = F_{1} sin θ + F_{2} = \frac{q _{1}}{4 π ε _{0}} [\frac{q _{3}}{a ^{2}} sin θ + \frac{q _{1}}{b _{2}}] \Rightarrow F_{X} \propto (\frac{q _{3}}{a ^{2}} sin θ + \frac{q _{2}}{b ^{2}})$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2003

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