Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

A load rises slowly from $2$ to $4 kg$ ; wire extension rises from $0.6$ to $1.2 mm$ . With $g = 10 m/ s^{2}$ , work done is:

Answer:

Solution:

$W = \frac{1}{2} (F_{1} + F_{2}) (x_{2} - x_{1})$ .

$W = \frac{1}{2} (20 + 40) (0.0006) = 1.8 \times 1 0^{- 2} J$ .

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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