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PhysicsElasticityMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

Rod of constant cross-section moves towards right with constant acceleration. Graph of stress and distance from left end is given as in figure. If density of material of rod at cross section 1 is $9 gm / cm^{3}$ . Find density at cross section 2.

Options:

Answer:

Solution:

$tan θ = \frac{d ( s t ress )}{dx}$

$= \frac{d F / A}{d x} = \frac{( d m ) a / A}{d x} = \frac{( ρ \cdot d ( v o l . )) a}{A d x}$

$tan θ^{'} = ρ a$ .

$\frac{tan 3 7 ^{\circ}}{tan 5 3 ^{\circ}} = \frac{ρ _{1}}{ρ _{2}} = \frac{9}{ρ _{2}}$

$ρ_{2} = 16 g m / c m^{3}$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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