Four cubes of ice at − 1 0 ∘ C each one gm is taken out from the refrigerator and are put in 150 gm of water at 2 0 ∘ C . The temperature of water when thermal equilibrium is attained. Assume that no

Question

Four cubes of ice at − 1 0 ∘ C each one gm is taken out from the refrigerator and are put in 150 gm of water at 2 0 ∘ C . The temperature of water when thermal equilibrium is attained. Assume that no heat is lost to the outside and water equivalent of container is 46 gm . (Specific heat capacity of water = 1 cal / gm − ∘ C , Specific heat capacity of ice = 0.5 cal / gm − ∘ C , Latent heat of fusion of ice = 80 cal / gm )

TestHub · Accepted Answer

Heat gained by ice = Heat lost by water + Heat lost by container Initial Temperature of container = 2 0 ∘ C 4 × 2 1 ​ × 10 + 4 × 80 + 4 × 1 × ( T − 0 ) = 196 × 1 × ( 20 − T ) 20 + 320 + 4 T = 196 × 20 − 196 T 200 T = 196 × 20 − 340 T = 200 3580 ​ = 17. 9 ∘ C

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