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PhysicsElasticityMiscellaneousEasy2 minPYQ_2022
PhysicsEasynumerical

A square aluminium (shear modulus is25×109Nm-2) slab of side60 cmand thickness15 cmis subjected to a shearing force (on its narrow face) of18.0×104 N. The lower edge is riveted to the floor. The displacement of the upper edge is _____μm.

Answer:
48.00
Solution:

Shearing stress is given by FA=ηxl

Thus, displacement is x=FlAη

x=18×104×60×10-260×10-2×15×10-2×25×109

=48×10-6 m=48 μm

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous
2mℹ️ Source: PYQ_2022

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