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PhysicsElasticityMiscellaneousEasy2 minPYQ_2021
PhysicsEasysingle choice

A uniform heavy rod of weight10 kg m s-2,cross-sectional area100 cm2and length20 cmis hanging from a fixed support. Young modulus of the material of the rod is2×1011 N m-2.Neglecting the lateral contraction, find the elongation of rod due to its own weight:

Options:

Answer:
A
Solution:

Elongation due to self weight,
Wl2AY=10×0.22×2×1011×100×10-4=5×10-10 m

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous
2mℹ️ Source: PYQ_2021

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